Secret Santa 2024
Original Post
Toribash in Numbers
Recently there's been talk about copying openers, possibilities and the like. For the past hour or so I've been really bored so I decided to calculate some probability factors:

Number of possible openers: 4398046511104

Number of possible combined openers: 19342813113834066795297716

Number of possible outcomes in a Toribash match with 120/10 frames, no fracture, dismemberment, or dq:
2,7430620343968443416279681255936^303



I for one then find it amazing how people can say that avoiding to copy openers, or moves in general is impossible. If everyone were introduced to Toribash in a closed cubical where they fought alone against uke, they would all try a different approach.

The "impossible" factor here, is the human mind. To become better, we naturally throw away our creativity and adapt to the style used by whoever rests above us on the food-chain.

My claim: There are still undiscovered openers that function just as well or better than the already "invented" ones, but none of us have had the mental width to find them yet.

Discuss.
Last edited by CMon; Oct 3, 2008 at 11:50 PM.
Number of possible openers: 4398046511104 How exactly did you come to that number? I counted 4096 000 000 00 different openers basing my calculation on that the first 2 turns counts towards the opener.


How many turns counts towards the opener in your case?


20 different joints with 4 different states, plus the grip factor, and taking into account the first two frames


(20^4x4)^2

20^4 = 16 00 00 (number of different openers in the first frame without taking into account wether you grip or not)

16 00 00 x 4 = 64 00 00 (number of different openers in the first frame when taking into account wether you grip or not)

64 00 00^2 = 4096 000 000 00 (number of different openers when taking the second turn and wether you grip or not into account.)

This is also assuming that none of the joints will break or get fractured.

For combined openers I get

4096 000 000 00 x 2 = 8192 000 000 00 different outcomes.
Last edited by Chronos; Oct 3, 2008 at 03:25 PM.
Originally Posted by Chrawnus View Post
How many turns counts towards the opener in your case?

I counted only the first turn.

My way of doing it:

- A joint has 4 states.
- Two joints would make 4 x 4 possible combinations:
AA
AB
AC
AD
BA
BB
BC
BD
CA
CB
CC
CD
DA
DB
DC
DD


Now, 20 joints + two hands with two possible states each (counts as 4 options) would make 4^21 possible combinations.

4^21 = 4398046511104


Originally Posted by Redwards View Post
Just cause there are that many openers that doesn't mean they are all good ones.

That's not my point. My point is that since there are over a billion possible openers, it's highly improbable (most likely impossible) that all effectual options have been tried or even remotely discovered yet.
Last edited by CMon; Oct 3, 2008 at 04:12 PM.
Just cause there are that many openers that doesn't mean they are all good ones.
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Originally Posted by Redwards View Post
Just cause there are that many openers that doesn't mean they are all good ones.

Just because not every undiscovered opener is good doesn't mean that there isn't a large number of them that aren't, if you want to take this even further.
But many of these openers would be counted the same because noone would call it a different opener when its just right instead of left and wether you relax hold contract or extend your neck.
I agree that some undiscovered openers might be better than the established ones, but if we all were to play 'in a box' many if not most people would still come up with the same kick (some would raise the shoulder some would lower)
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Originally Posted by DarkVadder View Post
But many of these openers would be counted the same because noone would call it a different opener when its just right instead of left and wether you relax hold contract or extend your neck.
I agree that some undiscovered openers might be better than the established ones, but if we all were to play 'in a box' many if not most people would still come up with the same kick (some would raise the shoulder some would lower)

It would still make a difference. Note how just relaxing a seemingly useless joint instead of I.e. extracting it may award you, say, 500 extra points.
Wouldn't that number be considerably less because as you move on, more and more options get eliminated. In my opinion, a large portion of your theorised openers would be duplicates.

eg. we have A B and C.

A would have A + B, A+C
B would have B + A (duplicate), B+C
C would have C+A (duplicate), C+B (duplicate)

Edit: THEORETICALLY, there are 6 different combos, but in reality theres only 3.

See?
Originally Posted by YoungBl00d View Post
Wouldn't that number be considerably less because as you move on, more and more options get eliminated. In my opinion, a large portion of your theorised openers would be duplicates.

eg. we have A B and C.

A would have A + B, A+C
B would have B + A (duplicate), B+C
C would have C+A (duplicate), C+B (duplicate)

Edit: THEORETICALLY, there are 6 different combos, but in reality theres only 3.

See?

I don't really get what you're on about.

You do not "eliminate" options. My grounds of calculation necessitates the same number of possibiliites every turn. For instance, without fracture, dq, or dismemberment, you would have the opportunity to contract pecs in all turns.
By eliminate i mean, taking that opener out of the total number of openers, on the grounds that it is a duplicate of another opener (eg. AB and BA)

So i mean, wouldn't your total number for openers be lessened?

Unless you've already taken duplicates into account.

And i thought we were just talking about openers, being first turn moves only.
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