The curve would have an asymptote at y=1 as 0.999... = 1. Also, you cannot draw any graph accurately enough to show an infinite level of detail.

he has a point, there's so such things as a strait line, or a perfect circle/curve...

No, but if you stand far enough away or get intoxicated. Anything looks perfect for the time being.

I once rendered a sphere with 1,000,000,000 polygons. it took a while to finish. each polygon was made up of smaller poly's by smaller poly's up to 10 times. The first set of polygons couldnt even be destinguished on the final render one from another. The image size was 1024x760 and the sphere took up 3/4 of the image size.

Sure - if you could zoom down close enough, nothing can be perfectly straight or curved. Hence the reason why we add numbers and reasons to everything for guidlines and sanity ^.^

So what you are really saying is that if you graph the line y=1 than y=2 would be on the line. :P If you graph it on a graph of a scale of 100000000000x10000000000000 so therefore 1 obviously = 2.

i didnt say that.

What i said was that you cannot create a graph with an infinite amount of detail. Just try to plot a fractal exactly - it's impossible.

Yeah. I notice on any program I use to graph, asymptotes always show up as lines sharply jumping from one side of the hole to the other. The program itself shows values that simply do not exist.

Anyway, as for what Slain just said... He's absolutely right. It's like trying to tell the difference between up and down quarks with the naked eye.

But you have to agree that theoretically there is an asymptote at y=1.

yes. But the argument you used was that there was no asymptote. Make your mind up :o

No what I said was that IF .999...=1 then there wouldnt be an asymptote therefor .999... does not =1

Regardless of if .999... = 1, the function y = 1/x + 1 has y = 1 as asymptote, since lim(x->∞) ( 1 / x ) = 0.