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Aug 20, 2011 Old
A math equation omegle couldn't figure out.
If 5x + 4y = poop, and y = 6, and poop is an even number, what are the possible even values for poop under 50, assuming x is a positive integer?

I'm suprised so few people got this, it's not higher than 6-7th grade math....
Put your answers in a spoiler, so only the people who want to see it will see it.
Last edited by suomynona; Aug 20, 2011 at 12:57 AM.
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*sigh*

As per request



It's still computer solvable.
Last edited by suomynona; Aug 20, 2011 at 12:46 AM.
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Originally Posted by suomynona View Post
*sigh*

x is -4, -2, 0, 2, or 4.

It's still computer solvable.

You're not solving for x.
You're solving for poop.
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Plug in x then.

As per request

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Originally Posted by NoCheerios View Post
If 5x + 4y = poop, and y = 6, and poop is an even number, what are the possible even values for poop under 50, assuming it's a positive integer?

Yeahhhh.... sorry, "it" refers to x.
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Uhh.

4, 14, 24, 34, and 44 are all positive integers, NoCheerios. Even, too.

Now, obviously, if x also has to be positive, then depending on what you count 0 as, you have maybe 24 and definitely 34 and 44.

But then you're just asking a poorly worded problem.
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Originally Posted by suomynona View Post
Uhh.

4, 14, 24, 34, and 44 are all positive integers, NoCheerios. Even, too.

Now, obviously, if x also has to be positive, then depending on what you count 0 as, you have maybe 24 and definitely 34 and 44.

But then you're just asking a poorly worded problem.

I was* now I'm not. And no, 0 doesn't count. But yeah.
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Aug 20, 2011 Old
Computer solvable, lol.
It's just 4 times 6 wich is 24.
50 less 24 is 26.
You can now subtract 10 or subtract 20 without getting into negatives, as suo explained.
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